How to use await with setTimeout [duplicate]

Question

// getData() function is returning null right now , but Actually I want to return a value after 1.5 seconds

showData = (data) => {
        console.log("showing" , data)
    }
    getData = async (a,b) => {
        let x = null;
        await setTimeout(() => {
            x = a*b;
            console.log(x) //200
        }, 1500);
        console.log(x); //null --should run after timeout
        return x;
    }
    getData(10,20);

use promise -> resolve ... developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Mister Jojo
– Mister Jojo, Commented Mar 5, 2023 at 14:42
await setTimeout will not await the timer to expire. For that you need a promise. — trincot
– trincot, Commented Mar 5, 2023 at 14:42

ProfDFrancis · Accepted Answer · 2023-03-05 14:47:33Z

-2

This will do it

async function getData (a, b) {
  return new Promise(resolve =>
    setTimeout(() => {
      const x = a * b;
      resolve(x)
    }, 1500)
  )
}

getData(10, 20).then(result => console.log(result));

answered Mar 5, 2023 at 14:47

ProfDFrancis

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How to use await with setTimeout [duplicate]

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This will do it

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