Print a string and call a class method (that contains 'input') in the same line

Question

So I want to print a string and then call a method, which is inside the class within the same line.

My code is following:

class A:
    
    def a(self):
        return 'bla bla\n' + A.b(self)
    
    def b(self):
        self.input = input('Type here:')
        if self.input == 'yes':
            return '\nok'
        else:
            return '\nnot ok'
    
d = A()

print(d.a())

The results I get:

Type here: (when I type 'Yes')

bla bla

ok

What I want is this:

bla bla

Type here: (when I type 'Yes')

ok

I want that 'bla bla' would be displayed first and then based on the input you would get either 'ok' or 'not ok'.

Can someone please help with what do I need to change?

Mixing concatenation of strings and printing directly will make this harder than it needs to be. b needs to be called before a can return, which means the input string will be printed first. I'd move the input-asking code out, pass the result into b, and have b make decisions based on already-received input. — Carcigenicate
– Carcigenicate, Commented Jul 1, 2021 at 14:08

PCM · Accepted Answer · 2021-07-01 14:08:43Z

1

Change method a like -

def a(self):
    print('bla bla\n')
    return A.b(self)

The print statement will execute first and then return method b and asks you the input

answered Jul 1, 2021 at 14:08

PCM

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1 Comment

NewLineCinema2 Over a year ago

Great idea! Thanks! Don't know how I didn't come up with that (am quite new in Python).

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